In an ap the sum of first n terms is 5n 2/2
WebThe sum of the first n term sofa an AP is ( 3 n 2 2 + 5 n 2). Find its nth term and the 25th term Advertisement Remove all ads Solution Let S denotes the sum of first n terms of the AP. ∴ s n = ( 3 n 2 2 + 5 n 2) ⇒ s n - 1 = 3 ( n - 1) 2 2 + 5 ( n - 1) 2 = 3 ( n 2 - 2 n + 1) 2 + 5 ( n - 1) 2 = 3 n 2 - n - 2 2 ∴ n th term pf the AP , a n WebNov 11, 2011 · Find the sum of first n terms if an AP whose nth term is 5n-1. Hence find the sum of first 20 terms Asked by 11 Nov, 2011, 04:16: PM Expert Answer n th term = 5n - 1 Put n=1, we get 1 st term = 5-1 = 4 Hence sum of n terms = n (First term + nth term)/2 = n (4+5n - 1)/2 = n (5n +3)/2 Sum of 20 terms becomes, put n = 20 S 20 = 20 (5×20 +3)/2
In an ap the sum of first n terms is 5n 2/2
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Web(11) Search the sum the first 20 terms of the numerical series in which 3 rl term is 7 also 7 in term is 2 more than three time its 3 rad term. Solution (12) Stylish an arithmetic series, which sum of first 11 conditions is 44 and one that of the next 11 terms is 55. WebThe sum of the first n terms of an AP in ( 5 n 2 2 + 3 n 2) .Find its nth term and the 20th term of this AP. Advertisement Remove all ads Solution s n = ( 5 n 2 2 + 3 n 2) = 1 2 ( 5 n 2 + 3 …
WebApr 20, 2024 · Apr 20, 2024 The sum of the first n term of an AP,denoted by Sn is given by Sn = n2 +8n So n th term of the series will be tn = Sn −Sn−1 = n2 + 8n − ((n −1)2 +8(n − 1)) ⇒ tn = 2n − 1 + 8 = 2n +7 Inserting n = 1,2,3.... we get For n = 1 → t1 = 2 ⋅ 1 +7 = 9 For n = 2 → t2 = 2 ⋅ 2 +7 = 11 For n = 3 → t3 = 2 ⋅ 3 +7 = 13 Hence first term t1 = 9 WebGeneral term of an AP is given by: a n = S n - S (n - 1) Calculation: Given: S n = 5n 2 + 6n and m th tem is 301. a n = S n - S (n - 1) After solving above equation we get . a n = 5(n) 2 + 6(n) - [5(n - 1) 2 + 6(n - 1)] a n = 5n 2 + 6n - 5n 2 - 5 + 10n - 6n + 6. a n = 10n + 1 . For 1st term, put n = 1. So, a 1 = 10 × 1 + 1 = 11. For 2nd term ...
WebLet S denotes the sum of first n terms of the AP. `∴ s_n = ( (3n^2) /2 +(5n) /2)` `⇒ s_(n-1) = (3(n-1)^2)/2 + (5 (n-1))/2` `= (3(n^2 - 2 n + 1 ))/2 + (5 (n-1))/2` `=(3n^2 - n-2)/2` ∴ n th term … WebMar 22, 2024 · It is given that kth term = 5k + 1 ak = 5k + 1 To find sum of n terms, we use the formula Sn = n/2 [a + l] where Sn = sum of n terms of AP n = number of terms a = first term of A.P l = last term of A.P.
WebThe sum of the first n terms of an AP is (5n^2/2 + 3n/2). Find its nth term and the 20th term of this AP. asked Jul 9, 2024 in Arithmetic Progression by Anaswara (31.5k points) …
WebThe sum of the first n terms of an AP in ( 5 n 2 2 + 3 n 2) .Find its nth term and the 20th term of this AP. Advertisement Remove all ads Solution s n = ( 5 n 2 2 + 3 n 2) = 1 2 ( 5 n 2 + 3 n) ..... (1) Replacing n by (n-1) in (i), we get: s n - 1 = 1 2 × [ 5 ( n - 1) 2 + 3 ( n - 1)] = 1 2 × [ 5 n 2 - 10 n + 5 + 3 n - 3] = 1 2 × [ 5 n 2 - 7 n + 2] list of schools in pretoria eastWebJan 8, 2024 · In an AP the sum of first n terms is 3n^2/2 + 5n/2 find the 25th term.In an AP the sum of first n terms is (3n^2+ 5n)/2 find the 25th term.In an AP the sum o... list of schools in peramburWebWhat is the Sum of n Terms of an AP Formula? The sum of n terms of an AP can be found using one of the following formulas: S n = n/2 (2a+(n−1)d) S n = n/2 (a 1 +a n) Here, a = a 1 = the first term, d = the common … immaculate conception church worcesterWebAug 28, 2024 · In an AP the sum of first n terms is 3n^2/2 + 5n/2 find the 25th term. Advertisement Expert-Verified Answer 1282 people found it helpful Brainly User Let the … immaculate conception church wexford iaWebMar 27, 2024 · Solution For 10] Find the sum of first ' n ' terms of an AP 2 ,8 ,18 ,32 , 11] If α,β and γ are the zeroes of the polynomial P(x)=x3−6x2−x+30 then fin. The world’s only live instant tutoring platform. Become a tutor About us Student login Tutor login. Login. Student Tutor. Filo instant Ask button for chrome browser. ... immaculate conception church truroWebMar 23, 2024 · The sum of the third and the seventh terms of an AP is 6 and their product is 8. Find the sum of first sixteen terms of the AP. 3. A ladder has rungs 25 cm apart. (see Fig. 5.7). The rungs decrease uniformly in length from 45 cm at the bottom to 25 cm at the top. list of schools in nswWebSolution Given that sum of the first n terms of an AP is 5n - n 2 Sn = 5n − n 2 First term, a 1 = S 1 = 5 (1) − (1) 2 = 5 − 1 = 4 Sum of first two terms = S 2 = 5 (2) − (2) 2 = 10 − 4 = 6. … immaculate conception clondalkin